Get list of last record for each ID in SQL

Question

I would like to get last records by every id_foreign in sql, example what I want to do:

input:

id: 1, id_foreign: 5, value: 1 
id: 2, id_foreign: 4, value: 2 
id: 3, id_foreign: 4, value: 3 
id: 4, id_foreign: 5, value: 4 
id: 5, id_foreign: 5, value: 5 

output:

id: 3, id_foreign: 4, value: 3 
id: 5, id_foreign: 5, value: 5

What about DISTINCT ? Any other idea? Understand me?

tried this solution:

SELECT * FROM table 
GROUP BY id_foreign 
ORDER BY id DESC

but outputs me:

id: 1, id_foreign: 5, value: 1 
id: 2, id_foreign: 4, value: 2 

I tried both (ASC and DESC) and bad output too.

Answer 1

A simple but not necessarily the most optimal way of querying this is using NOT EXISTS :

SELECT *
FROM MyTable t
WHERE NOT EXISTS (
    SELECT * FROM MyTable tt WHERE tt.id_foreign=t.id_foreign AND tt.id > t.id
)

Demo on SqlFiddle.