How do I convert String to Long with two significant digits in Java?

Question

I am trying to get 123456789.12 value out of 123456789.1234

If i use strings, it will be worked straightaway using parsing logic. I don't want to return String. requirement is to return Long.

Here i would like return the output the Long type rather than string..can someone help me on this?

Answer 1

Long is an integer type, and thus can not hold a decimal. Trying to use Long.parseLong would result in a NumberFormatException . You need to use a representation that deals with the scale as well.

Answer 2

try this for long output:

String str = "123456789.1234";
BigInteger num = new BigInteger(str);

return num.longValue();

try this for float output:

String str = "123456789.1234";
BigDecimal num = new BigDecimal(str).setScale(2, BigDecimal.ROUND_HALF_UP);

return num.floatValue();

Answer 3

The number which you want to return it is not Long.You can return double or float.Also you can use

DecimalFormat df = new DecimalFormat("#.##");
String stringDouble = df.format(yourDouble);;