I want to create a fixed size integer in python, for example 4 bytes. Coming from a C background, I expected that all the primitive types will occupy a constant space in memory, however when I try the following in python:
import sys
print sys.getsizeof(1000)
print sys.getsizeof(100000000000000000000000000000000000000000000000000000000)
I get
>>>24
>>>52
respectively.
How can I create a fixed size (unsigned) integer of 4 bytes in python? I need it to be 4 bytes regardless if the binary representation uses 3 or 23 bits, since later on I will have to do byte level memory manipulation with Assembly.
You can use struct.pack
with the I
modifier (unsigned int). This function will warn when the integer does not fit in four bytes:
>>> from struct import *
>>> pack('I', 1000)
'\xe8\x03\x00\x00'
>>> pack('I', 10000000)
'\x80\x96\x98\x00'
>>> pack('I', 1000000000000000)
sys:1: DeprecationWarning: 'I' format requires 0 <= number <= 4294967295
'\x00\x80\xc6\xa4'
You can also specify endianness .
the way I do this (and its usually to ensure a fixed width integer before sending to some hardware) is via ctypes
from ctypes import c_ushort
def hex16(self, data):
'''16bit int->hex converter'''
return '0x%004x' % (c_ushort(data).value)
#------------------------------------------------------------------------------
def int16(self, data):
'''16bit hex->int converter'''
return c_ushort(int(data,16)).value
otherwise struct can do it
from struct import pack, unpack
pack_type = {'signed':'>h','unsigned':'>H',}
pack(self.pack_type[sign_type], data)
you are missing something here I think
when you send a character you will be sending 1 byte so even though
sys.getsizeof('\x05')
reports larger than 8 you are still only sending a single byte when you send it. the extra overhead is python methods that are attached to EVERYTHING in python, those do not get transmitted
you complained about getsizeof
for the struct pack answer but accepted the c_ushort answer so I figured I would show you this
>>> sys.getsizeof(struct.pack("I",15))
28
>>> sys.getsizeof(c_ushort(15))
80
however that said both of the answers should do exactly what you want
I have no idea if there's a better way to do this, but here's my naive approach:
def intn(n, num_bits=4):
return min(2 ** num_bits - 1, n)
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