How to match a string contain specific text preceded by any combination of alphanumerics and other charcters in regex

Question

I want to match strings which have a specific text in start but after that any combination of alphanumeric and character value and string ends with double quotes " . Here is the sample string

fixed_words_/abcd123/"

in this string, fixed_words_ will always be same and in the end will be " but in between there can be digits, alphabets, underscores and slashes.

I tried mystring.match(/fixed_words_\\w*"/g) but its not working. I am sorry but I am new to regex so don't mind if its a stupid question.

Answer 1

Instead of \\w , have a character class that can match either \\w (alphanumerics/underscores) or a slash:

mystring.match(/fixed_words_[\/\w]*"/g)

The above assumes that your expression can appear anywhere (or multiple times!) in mystring . If you want mystring to contain only your expression, add a start-of-string anchor ( ^ ) at the beginning, an end-of-string anchor ( $ ) at the end, and get rid of the g flag permitting multiple matches:

mystring.match(/^fixed_words_[\/\w]*"$/)

Answer 2

Use the following regex to match your string: ^\\s*fixed_words_[^"]"\\s*$

[^"]* will match all the characters until it finds a double quote ( " ) character.