why char ch =4 (without '') , is not error?

Question

I want to know why char ch =5; (for example) is not error ? but if I print

System.out.println(Character.isDigit(ch));
// output 

false

it will be false ?

Answer 1

Because 5 is an integer literal that can be converted to a char . It is not the character '5' however.

Answer 2

A character is represented by two bytes in memory. Java converts 5 to a character. '5' is not the 6th character (its hexadecimal code is 35 and not 5) in the ASCII table and is thus not a "digit".

Answer 3

try this example :

 char ch = 97;
 JOptionPane.showMessageDialog(null,"ch = "+ch);

The answer would be : ch = a

It simply won't give an error even though 97 is without (' ') because 97 represent the ASCII code for the character 'a' so it's not a digit , and that's why you are getting false as a result.

Answer 4

如果你给ch = 5 ，它会根据ASCII值自动转换为char。