Replacing words in shell command

Question

I'm a bit new at this so bear with me. I would like to replace certain text that is attached to a variable? or is it string? i can't remember what the dickens it's called.

delete me /from/this/here/string/

var="delete me /from/this\ here\ string/"

i tried:

echo $var | sed 's/^\(.* \)\(delete\sthis \)$/\wtf?\1/g'
echo $var | sed 's/.*\//delete this;/g'
awk ${var/123/abc};

I would like to git riddens of the 'delete me' printing. the second part always changes, but 'delete me' is always present. i'm too old for this, so thank you

Answer 1

Try this

> var="delete me /from/this\ here\ string/"
> echo "${var/delete me/}"
 /from/this\ here\ string/

Answer 2

这个怎么样？

echo $var|sed 's/\(^[^/]*\)/abc/'

Answer 3

var="delete me /from/this\ here\ string/"

var="$(printf '%s' "$var" | sed -e 's/^[[:blank:]]*delete[[:blank:]][[:blank:]]*[^[:blank:]]*[[:blank:]]*//' -e 's/\\//g')"

echo "$var"

My output:

/from/this here string/

It simply substitutes the word "delete" and a word following it, removing all space before and after the phrase of course. This allows it to work on "delete me", "delete this", and even "\\t \\t delete \\t \\t \\t me_too \\t \\t \\t" because a "blank" is a space or a tab character (\\t). It will only work for two words starting with "delete" at the beginning.

I hope this helps.