private String theLetters = "_ _ _ _ _\n";
StringBuilder myName = new StringBuilder(theLetters);
for(char e : theSecretWord.toLowerCase().toCharArray())
{
if(e == theUsersGuess.charAt(0))
{
int index = theSecretWord.indexOf(e) * 2;
myName.setCharAt(index, theUsersGuess.charAt(0));
theLetters = myName.toString();
}
}
For some reason this will only replace the first occurrence of a letter from the String theSecretWord and not the second, even though this for each loop goes through each character and replaces it in theLetters accordingly. I don't understand why it won't replace more than one occurrence of a letter.
I think it's because the loop stops once it finds a matching letter even though it shouldn't.
I think this is the code you're looking for,
String word, letter;
word = "test";
letter = "t";
int i = 0;
i = word.indexOf(letter);
while (i > -1) {
// store i in arrayList
i = word.indexOf(letter, i + 1);}
Another Way is
String string1= "Hello";
int first=string1.indexOf('l');
String newstr= string1.substring(0, first+1);
String newstr2= string1.substring(first+1, string1.length()).replaceFirst("l", "k");
System.out.println(newstr+newstr2);
By using StringBuilder you can achieve this by using below code
String string1= "Hello";
int first=string1.indexOf('l',string1.indexOf('l')+1);
StringBuilder SB = new StringBuilder(string1);
SB.setCharAt(first, 'k');
System.out.println(SB);
private String replaceOccurance(String text, String replaceFrom, String replaceTo, int occuranceIndex)
{
StringBuffer sb = new StringBuffer();
Pattern p = Pattern.compile(replaceFrom);
Matcher m = p.matcher(text);
int count = 0;
while (m.find())
{
if (count++ == occuranceIndex - 1)
{
m.appendReplacement(sb, replaceTo);
}
}
m.appendTail(sb);
return sb.toString();
}
For example if you want to replace the second occurance of "_" with "A", then:
String theLetters = "_ _ _ _ _\n";
String replacedText = replaceOccurance(theLetters, "_", "A", 2);
Result: _ A _ _ _
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