Java: Convert floating point decimal number to the power of to integer

Question

So I have the following number

3.454545E5

Notice the "E" letter which indicates to the power of

Is there a way to conver this number to

3454545

?

Answer 1

double d = 3.454545E5;
int i = (int) d;

Output: 345454.

If you want exactly 3454545:

int i = (int) (d*10);

Answer 2

You can use DecimalFormat to format the number any way you want.

If it is a string, first parse it as a double.

Answer 3

double yourNumber = 3.454545E5;
String output = String.format("%d", yourNumber);

Answer 4

尝试这个

long l = (long) 3.454545E5;

Answer 5

Can you try doing this?

    double num = 3.454545E5;
    int num1 = (int)num;

    System.out.println(num1);

Here is the result - 345454

Answer 6

Not sure if I understand you correctly but looks like you're interested in extracting mantissa from the number and dropping the exponent

This should work for you:

double number = 3.454545E5;  
int exponent = (int)Math.log10(Math.abs(number));  // exponent = 5
double mantissa = number / Math.pow(10, exponent); // mantisa = 3.454545

To get your number you can multiply mantissa, in your particular example:

int result = (int)(mantissa * 1000000)
//result = 3454545