How Do I Take Out Only Numbers From A PHP String?

Question

Suppose, I have this string:

$string = "Hello! 123 How Are You? 456";

I want to set variable $int to $int = 123456;

How do I do it?

Example 2:

$string = "12,456";

Required:

$num = 12456;

Thank you!

Answer 1

Correct variant will be:

$string = "Hello! 123 How Are You? 456";
$int = intval(preg_replace('/[^0-9]+/', '', $string), 10);

Answer 2

You can use this method to select only digit present in your text

function returnDecimal($text) {
    $tmp = "";  
    for($text as $key => $val) {
      if($val >= 0 && $val <= 9){
         $tmp .= $val
      }
    }
    return $tmp;
}

Answer 3

You can use the below:

$array = [];

preg_match_all('/-?\d+(?:\.\d+)?+/', $string, $array);

Where $string is the entered string and $array is where each number(not digit!,including also negative values!) is loaded and available for different more operations.

Answer 4

Use this regular expression !\\d!

<?php
$string = "Hello! 123 How Are You? 456";
preg_match_all('!\d!', $string, $matches);
echo (int)implode('',$matches[0]);

Answer 5

$str = 'In My Cart : 11 items';
$int = (int) filter_var($str, FILTER_SANITIZE_NUMBER_INT);

Answer 6

<?php
    $string = "ABC100";
    preg_match_all('!\d+!', $string, $matches);
    $number = $matches[0][0];
    echo $number;
?>

Output: 100