How to read from a string and split certain words?

Question

I have a text which I need to read word by word till ';' delimiter... I have searched in many places and also i have read some chapters but I can't find any method to use... Please help!

string to read ie 32; Potatoe; Vegetables; 21.30; 12.20; 15 21 32 45;

Answer 1

String s = "32; Potatoe; Vegetables; 21.30; 12.20; 15 21 32 45;";
String[] splittedWords;

splittedWords = s.split(";");

You can use the method split to seperate words along delimiters. It will return a list of Strings. If you want to parse the values in the string to an Integer you can use this:

for (String string : splittedWords)
    {
        if(string.matches("[^a-z \\.]+")==true)
        {
            int value = Integer.parseInt(string);

            System.out.println(value);
        }
    }

the only integer in your samplestring is 32, though. Thats why this code will only output "32".

Answer 2

Try this:

for ( String s : myOwnString.split(";") ){
    System.out.println(s);
}

Answer 3

Java supports this very clearly, with the String.split() method. You can read the documentation here .

String[] tokens = input.split(";");

// tokens contains each value.

Answer 4

You can use split method of String .

String string = "32; Potatoe; Vegetables; 21.30; 12.20; 15 21 32 45";
String[] split = string.split(";");

for(String s: split)
{
     System.out.println(s);
}

This will print:

32
Potatoe
Vegetables
21.30
12.20
15 21 32 45

Answer 5

String text = "32; Potatoe; Vegetables; 21.30; 12.20; 15 21 32 45";
String[] words = new String[text.length()];
int initialIndex = 0,i=0;

while (initialIndex<text.length()) {
    words[i] = text.substring(initialIndex, text.indexOf(";"));
    i++;
    initialIndex = text.indexOf(";")+1;
    }

Now String of words contains all words in text. You can access by word.get(index);