Convert DateTime Format in C#

Question

How can I convert this datetime format from a webservice? The datetime value is: "timestamp": "2014-04-18T14:45:00+02:00" I wan't to convert it to: dd.mm.YYYY hh.mm.ss

Answer 1

You need to use "yyyy-MM-dd'T'HH:mm:ssK" format with InvariantCulture using DateTime.ParseExact method like;

string s = "2014-04-18T14:45:00+02:00";
var date = DateTime.ParseExact(s, "yyyy-MM-dd'T'HH:mm:ssK",
                                   CultureInfo.InvariantCulture);

Take a look at The "K" Custom Format Specifier

Then you can get string representation of your DateTime with DateTime.ToString() method. DateTime has no inherent format, it has just a value. You can get string representation for formatting.

date.ToString("dd.MM.yyyy HH.mm.ss", CultureInfo.InvariantCulture);
//18.04.2014 03.45.00

Here a demonstration .

Remember, mm is for minutes, MM for months. And hh is for 12-hour clock which is 01 to 12 . But HH is 24-hour clock which is 00 to 23 .

That's why you can't parse 14 with hh specifier. I assume your real representation format is dd.MM.yyyy HH.mm.ss

EDIT : After your comment , you can use "MM/dd/yyyy HH:mm:ss" format like;

string s = "04/18/2014 14:45:00";
var date = DateTime.ParseExact(s, "MM/dd/yyyy HH:mm:ss",
                                   CultureInfo.InvariantCulture);
Console.WriteLine(date); // 18/04/2014 14:45:00

Answer 2

Use DateTime.ParseExact(string, string, IFormatProvider) or DateTime.TryParseExact(string, string, IFormatProvider, DateTimeStyles, out DateTime ).

• DateTime.ParseExact()
• DateTime.TryParseExact()

Answer 3

With a regex you can do the following:

string resultString = null;
try {
    resultString = Regex.Replace(subjectString, @"(\d{4})-(\d{2})-(\d{2})\w{1}(\d{2}):(\d{2}):(\d{2})\+\d{2}:\d{2}", "$3.$2.$1 $4.$5.$6", RegexOptions.IgnoreCase);
} catch (ArgumentException ex) {
    // Syntax error in the regular expression
}

//18.04.2014 14.45.00

Answer 4

string date = "2014-04-18T14:45:00+02:00";
var results = DateTime.ParseExact(s, "yyyy-MM-dd'T'HH:mm:ssK", CultureInfo.InvariantCulture);