I have a list of floats in Python and when I convert it into a string, I get the following
[1883.95, 1878.3299999999999, 1869.4300000000001, 1863.4000000000001]
These floats have 2 digits after the decimal point when I created them (I believe so),
Then I used
str(mylist)
How do I get a string with 2 digits after the decimal point?
======================
Let me be more specific, I want the end result to be a string and I want to keep the separators:
"[1883.95, 1878.33, 1869.43, 1863.40]"
I need to do some string operations afterwards. For example +=" \t "
.
Inspired by @senshin the following code works for example, but I think there is a better way
msg = "["
for x in mylist:
msg += '{:.2f}'.format(x)+','
msg = msg[0:len(msg)-1]
msg+="]"
print msg
Use string formatting to get the desired number of decimal places.
>>> nums = [1883.95, 1878.3299999999999, 1869.4300000000001, 1863.4000000000001]
>>> ['{:.2f}'.format(x) for x in nums]
['1883.95', '1878.33', '1869.43', '1863.40']
The format string {:.2f}
means "print a fixed-point number ( f
) with two places after the decimal point ( .2
)". str.format
will automatically round the number correctly (assuming you entered the numbers with two decimal places in the first place, in which case the floating-point error won't be enough to mess with the rounding).
map(lambda n: '%.2f'%n, [1883.95, 1878.3299999999999, 1869.4300000000001, 1863.4000000000001])
map()
为作为第二个参数传递的列表/迭代中的每个元素调用第一个参数中传递的可调用对象。
如果您想保持完全精度,语法上最简单/最清晰的方法似乎是
mylist = list(map(str, mylist))
Get rid of the ' marks:
>>> nums = [1883.95, 1878.3299999999999, 1869.4300000000001, 1863.4000000000001]
>>> '[{:s}]'.format(', '.join(['{:.2f}'.format(x) for x in nums]))
'[1883.95, 1878.33, 1869.43, 1863.40]'
str([round(i, 2) for i in mylist])
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