preg_match for string not work

Question

i have string like p88t9014-name here is p is for Product and t for sub product id and after - the name is user defined any name. i try to match string with preg_match with this code ::

$name="p88t0056-name";
if(preg_match('/p[0-9]t[0-9]-[A-Z,a-z]/',$name,$match)) {
    echo "yes";
} else {
    echo "No";
}
print_r($m);

i just try to match formate if is this with format p[number]t[number]-[anystring] . but my code is not working.

Answer 1

您需要在字符类之后放置量词：

'/p[0-9]+t[0-9]+-[A-Za-z]+/'

Answer 2

This regex will work for you:

/p(\\d+)t(\\d+)-(\\w+)/g

Demo

Explaination:

p matches letter p

\\d+ matches numbers 0-9

t matches letter t

\\d+ matches numbers 0-9

- matches dash '-'

\\W+ match any word character [a-zA-Z0-9_] and g to catch all matches.

I am also not an expert on regex but trying multiple options on http://www.regex101.com helps as it shows explanations of characters in right side panel. Hope it helps in future :)

Answer 3

If you're always going to have a set number of digits, you can also use:

 /^p[0-9]{2}t[0-9]{4}-[A-Za-z]+$/

Here's an example on RegExr: http://www.regexr.com/390ds

Answer 4

in regex [0-9] matches exactly one character, and so does [AZ,az] , and therefore $name is not match the pattern you give. Strings like "p8t0-A" and "p0t2," pass the test.

Besides, another problem in your pattern is that: [AZ,az] matches not only alphabets but also , (a single comma). I guess the pattern you need is p[0-9]+t[0-9]+-[A-Za-z]+ , in which + s represent "occurs at least once".