This is my string:
================================================================================
INPUT FILE
================================================================================
NAME = CO-c0m1.txt
| 1> ! HF def2-TZVP opt numfreq
| 2>
| 3> % scf
| 4> convergence tight
| 5> end
| 6>
| 7> * xyz 0 1
| 8> C 0 0 0
| 9> O 0 0 1
| 10> *
| 11>
| 12> ****END OF INPUT****
================================================================================
I want get this output:
! HF def2-TZVP opt numfreq
% scf
convergence tight
end
* xyz 0 1
C 0 0 0
O 0 0 1
*
I've been trying to do for like 5 hours and can't do it, please help, this is my pregmatch:
$regx = '/INPUT FILE...................................................................................(.*?)........................END OF INPUT/s';
if(preg_match($regx, $source[$i], $matches)) {
$input[$i] = preg_replace('/\s\s\s\s+/', "\n", $matches[1]);
}
I'am very new to regex and seems to be so hard. Can someone please help me, thanks in advance :)!
$p ="/[|]\s*\d*[>]\s(.+)/";
$t = "================================================================================
INPUT FILE
================================================================================
NAME = CO-c0m1.txt
| 1> ! HF def2-TZVP opt numfreq
| 2>
| 3> % scf
| 4> convergence tight
| 5> end
| 6>
| 7> * xyz 0 1
| 8> C 0 0 0
| 9> O 0 0 1
| 10> *
| 11>
| 12> ****END OF INPUT****
================================================================================";
preg_match_all($p,$t,$res);
die(json_encode($res[1], JSON_PRETTY_PRINT));
/* Output:
[
"! HF def2-TZVP opt numfreq",
"% scf",
" convergence tight",
"end",
"* xyz 0 1",
"C 0 0 0",
"O 0 0 1",
"*",
" ****END OF INPUT****"
]
*/
Second item of $res
is an array that have what you want.
You need a regular expression that matches the lines that start with |
followed by some spaces, then one or more digits then >
and you need only the text that follows this prefix.
The regular expression is: /^\\|\\s*\\d+>(.*)$/m
. It contains a capturing group for the text you need. preg_match_all()
puts the capturing fragments in $matches[1]
:
preg_match_all('/^\|\s*\d+>(.*)$/m', $source[$i], $matches);
echo(implode("\n", $matches[1]));
You can then remove the line that contains ****END OF INPUT****
by other means ( array_pop()
, array_filter()
, etc.)
Check it in action: https://3v4l.org/hUEBk
The regex
explained:
/ # regex delimiter
^ # match the beginning of the line
\| # match '|' (it needs to be escaped because it is a meta-character)
\s # match a whitespace character (space, tab)
* # the previous (a whitespace) can appear zero or more times
\d # match a digit (0..9)
+ # the previous (a digit) can appear one or more times
> # match '>'
( # begin of a capturing group
.* # match any character, any number of times
) # end of the capturing group
$ # match the end of the line
/ # regex delimiter
m # multiline (regex modifier); check the regex against each line of the input string
Read more about Perl-Compatible Regular Expressions in PHP .
You don't need to run first regex on your text, only run this regex:
preg_match_all("/[|]\s*\d*[>]\s(.+)/", $source[$i], $matches);
echo(implode("\n", $matches[1]));
This works fine in my tests.
You may have a single regex solution to get all those data in one go:
^\|\h+\d+>(?!\h*\Q****END OF INPUT****\E)\h\K.+
Breakdown:
^
Match beginning of line \\|\\h+\\d+>
Match up to digit>
(?!
Start of a negative lookahead
\\h*
If horizental whitespace(s) exist(s) \\Q****END OF INPUT****\\E
And ends with end of input )
End of lookahead \\h\\K
Match a horizental whitespace then reset match .+
Match up to the end of line PHP code:
preg_match_all("~^\|\h+\d+>(?!\h*\Q****END OF INPUT****\E)\h\K.+~mi", $str, $matches);
Output of print_r($matches[0]);
:
Array
(
[0] => ! HF def2-TZVP opt numfreq
[1] => % scf
[2] => convergence tight
[3] => end
[4] => * xyz 0 1
[5] => C 0 0 0
[6] => O 0 0 1
[7] => *
)
You need to do a implode(PHP_EOL, $matches[0]);
to join values together.
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