How to find this pattern with grep in a shell script?

Question

How can i find this pattern in grep?

1.1.1.1 (everything) testString (everything)

I means i need a search that can find out if testString is there in each of this case:

1.1.1.1 test1 testString test2
1.1.1.1 test1 test2 testString
1.1.1.1 testString test1 test2

Then, how can i get the result of the grep in form of "false" (not found) or "true" (found it) in order to pass the result to an if clause inside a shell sh script?

Answer 1

Your question isn't very clear. Are you looking for testString or 1.1.1.1 followed by testString ?

Assuming the second case, and assuming you're reading in from a file:

while read line; do
  echo $line | grep -q '1\.1\.1\.1.*testString' && echo found || echo not found
done < filename.txt