The following code isn't working as expected ..
#include <stdio.h>
#include <unistd.h>
#include <string.h>
#include <stdbool.h>
struct dest
{
char filename[20], keyword[20];
bool opened;
FILE * stream;
};
void display_data(const struct dest p) {
printf("Keyword: %s, Filename: %s, Used: %s\n", p.keyword, p.filename, p.opened ? "Yes" : "No");
}
int main(int argc, char const *argv[])
{
// float lon, lat;
// char info[80];
if ((argc+1) % 2) {
fprintf(stderr, "Usage: %s file_to_read file_for_unknown type file type file ...\n", argv[0]);
return 2;
}
if (access(argv[1], F_OK) == -1) {
fprintf(stderr, "File can't be accessed: %s\n", argv[1]);
return 2;
}
const short pairs = (argc-3)/2;
struct dest data[pairs];
short times = 4;
for(short i = 4; i < argc; i += 2) {
struct dest data[i-times];
data[i-times].opened = false;
strcpy(data[i-times].keyword, argv[i-1]);
strcpy(data[i-times].filename, argv[i]);
// display_data(data[i-times]);
times += 1;
}
display_data(data[0]);
return 0;
}
That's what happens when I try to run it ..
./categorize spooky.csv other.csv UFO UFOS.csv
Keyword: ?, Filename: @, Used: No
Which isn't that meaningful ..
I have been trying to work out the solution .. in vein ..
I don't understand where the problem is ..
Arguments are parsed as follows:
: the file the program is supposed to read from (ignored for now) :程序应从中读取的文件(目前忽略)
: the file the program is supposed to store at any unknown info found in the spooky.csv file (also, ignored in this implementation) :程序应该在spooky.csv文件中找到的任何未知信息处存储的文件 (在此实现中也被忽略)
: they are parsed as pairs, the first is the keyword, the second is the file .. :它们被解析为对,第一个是关键字,第二个是文件..
My Solution for this filtering problem was to create an array of structs, and within each struct I store the keyword, the filename and the file io stream (which i am ignoring, for now) ..
Any help would be highly appreciated ..
You have 2 struct dest data[]
arrays. The inner one is masking the outer - get rid of it.
Your compiler is probably warning about this, if you have warnings turned on.
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