Use Regex to accept a string as long as it contains alphabet

Question

I want to accept a string as long as it contains alphabetical letters, for example: String testStr = "hello world 1. ?"

I am currently using this: testStr.matches("^[a-zA-Z\\\\s]+") , but it won't accept strings that have characters outside of the alphabet.

So I am wondering how to use regex in this situation.

Answer 1

Could use a lookahead to check if the string contains at least one [az]

(?i)^(?=.*[a-z]).*

Or without the i-caseless modifier : ^(?=.*[a-zA-Z]).* / Check only: ^(?=.*[a-zA-Z])

test at regex101