Algorithm to split string with comma only in the outer braces

Question

I want to split string only inside the first braces. How can I do it in java

Input String 1: text2(text3, text4), text5(text6, text7)

String1: text2(text3, text4)
String2: text5(text6, text7)

Input String 2: text2, text3(text4, text5(text6, text7, text8))

String1: text2
String2: text3(text4, text5(text6, text7, text8))

Input String can have arbitrary number of levels. Please assume that the input string has matching braces.

Thanks in advance

Answer 1

package ic.ac.uk.relationshipvisualiser.app;

import java.util.ArrayList;
import java.util.List;

public class tmpTest3 {

    public static List<String> process(String p_inp) {
        List<String> res = new ArrayList<String>();
        p_inp = p_inp.trim();

        int numberOfOpenBracketsEncountered = 0;

        String t = "";
        String cur = "";

        for (int c=0;c<p_inp.length();c++) {
            cur = p_inp.substring(c,c+1);
            if (cur.equals("(")) {
                numberOfOpenBracketsEncountered++;
            }
            if (cur.equals(")")) {
                numberOfOpenBracketsEncountered--;
            }


            if (cur.equals(",")) {
                if (numberOfOpenBracketsEncountered==0) {
                    if (t.length()>0) res.add(t.trim());
                    t = "";
                } else {
                    cur = cur;
                    t = t + cur;
                }
            } else {
                cur = cur;
                t = t + cur;
            }

        }
        if (t.length()>0) res.add(t.trim());

        return res;
    }

    public static void main(String[] args) {
        System.out.println("Start tmpTest3");

        List<String> inputs = new ArrayList<String>();
        inputs.add("text2(text3, text4), text5(text6, text7)");
        inputs.add("text2, text3(text4, text5(text6, text7))");

        for (int c=0;c<inputs.size();c++) {
            System.out.println("Running test for " + inputs.get(c));
            List<String> res = process(inputs.get(c));
            System.out.println("Got " + res.size() + " strings as a result:");

            for (int d=0;d<res.size();d++) {
                System.out.println(" - :" + res.get(d) + ":");
            }

            System.out.println("----------------------");

        }


        System.out.println("End tmpTest3");
    }   
}

Answer 2

Will This works for you ..?

import java.util.Arrays;

class Program {
public static void main (String[] args) throws java.lang.Exception  {

    String subject1 = "text2(text3, text4), text5(text6, text7)";
    String subject2 = "text2, text3(text4, text5(text6, text7))";
    String p = "\\s*\\d*\\(\\)";
    String[] res = subject1.split(p);
    System.out.println(Arrays.toString(res));
    res=subject2.split(p);
    System.out.println(Arrays.toString(res));

} // end main
} // end 

Out put :- [text2(text3, text4), text5(text6, text7)] [text2, text3(text4, text5(text6, text7))]