python regex find characters from and end of the string

Question

svn-backup-test,2014/09/24/18/Rev1223/FullSvnCheckout.tgz

from the following string I need to fetch Rev1233. So i was wondering if we can have any regexpression to do that. I like to do following string.search ("Rev" uptill next /)

so far I split this using split array s1,s2,s3,s4,s5 = string ("/",4)

Answer 1

You don't need a regex to do this. It is as simple as:

 str = 'svn-backup-test,2014/09/24/18/Rev1223/FullSvnCheckout.tgz'
 str.split('/')[-2]

Answer 2

Here is a quick python example

>>> impot re
>>> s = 'svn-backup-test,2014/09/24/18/Rev1223/FullSvnCheckout.tgz'
>>> p = re.compile('.*/(Rev\d+)/.*')
>>> p.match(s).groups()[0]
'Rev1223'

Answer 3

Find second part from the end using regex, if preferred:

/(Rev\d+)/[^/]+$

http://regex101.com/r/cC6fO3/1

>>> import re
>>> m = re.search('/(Rev\d+)/[^/]+$', 'svn-backup-test,2014/09/24/18/Rev1223/FullSvnCheckout.tgz')
>>> m.groups()[0]
'Rev1223'