Displaying information from a 2d array

Question

I'm trying to display the names from my 2d array.

public class last{

static void afficherMINU(String[][]nomPre){
    for(int i=0;i<nomPre.length;i++){
        for(int j=0;j<nomPre.length;j++){
            System.out.printf(nomPre[i][j]+"\n");
        }
    }
}

public static void main(String []args){
    String[]codePerm={"VILC15539307","NDIJ19129406","LANM29089409","JEAJ03108909","TOUS17529409","TRED01039200","AUCM28579305"};
    String[][]nomPre={{"VILLENEUVE-ASSE","CINDY"},{"NDIAYE YEND","JEAN-LOUIS RUDY"},{"LANDRY-VIGNEAULT GARCIA","MARCEL"},{"JEAN-BAPTISTE","JOSEPH-RAYMOND MARC"},{"TOUCHETTE","SOPHIE ANNE-MARIE"},
    {"TREMBLAY","DENIS MARC-ANDRE PIERRE"},{"AUCLAIR-JULIEN","MARIE-ISABELLE"}};

    afficherMINU(nomPre);

    }
}

The first information from "String[][]nomPre" in the double array is the last name followed by their name. For example when i display the array it should look like

VILLENEUVE-ASSE, CINDY
NDIAYE YEND, JEAN-LOUIS RUDY 

and so on. But my code keeps printing:

VILLENEUVE-ASSE
CINDY
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 2
    at last.afficherMINU(last.java:6)
    at last.main(last.java:16)

Answer 1

Your inner loop has the wrong termination bound. The value of nomPre.length is 7 (if I counted correctly), but the inner loop needs to stop after the length of nomPre[i] , since that's what's indexed by j . Use this instead:

for(int j=0;j<nomPre[i].length;j++){ // NOT nomPre.length
    System.out.printf(nomPre[i][j]+"\n");
}

Better yet, capture the i ^th row in the outer loop:

for(int i=0;i<nomPre.length;i++){
    String[] row = nomPre[i];
    for(int j=0;j<row.length;j++){
        System.out.printf(row[j]+"\n");
    }
}

Answer 2

In afficherMINU , this

for(int j=0;j<nomPre.length;j++) {

should be

for(int j=0;j<nomPre[i].length;j++) {

Or use, Arrays.deepToString(Object[]) like

System.out.println(Arrays.deepToString(nomPre));

Or use a for-each loop,

for(String[] arr : nomPre){
  System.out.println(Arrays.toString(arr));
}