Creating a function that returns all capitalized words in a sentence (commas excluded)

Question

I need to create a function that will return all capitalized words from a sentence into a list. If the word ends with a comma, you need to exclude it (the comma). This is what I came up with:

def find_cap(sentence):
    s = []
    for word in sentence.split():
        if word.startswith(word.capitalize()):
            s.append(word)
        if word.endswith(","):
            word.replace(",", "")
    return s

My problem: The function seems to work, but if I have a sentence and a word is in quotes, it returns the word in quotes even if it isn't capitalized. Also the commas aren't replaced, even though I used word.replace(",", "") . Any tips would be appreciated.

Answer 1

Strings are an immutable type in Python. This means that word.replace(",", "") will not mutate the string word is pointing at; it will return a new string with the commas replaced.

Also, since this is a stripping problem (and commas are not likely to be in the middle of words), why not use string.strip() instead?

Try something like this:

import string

def find_cap(sentence):
    s = []
    for word in sentence.split():

        # strip() removes each character from the front and back of the string
        word = word.strip(string.punctuation)

        if word.startswith(word.capitalize()):
            s.append(word)
    return s

Answer 2

Use regular expression to do this:

>>> import re
>>> string = 'This Is a String With a Comma, Capital and small Letters'
>>> newList = re.findall(r'([A-Z][a-z]*)', string)
>>> newList
['This', 'Is', 'String', 'With', 'Comma', 'Capital', 'Letters']

Answer 3

using re.findall :

  a= "Hellow how, Are You"
  re.findall('[A-Z][a-z]+',a)
  ['Hellow', 'Are', 'You']