How do I make a for loop that would go through a prior method?

Question

My current code is in two methods. I am trying to get the first position to switch with the second. For example, some on input 6 & 7. I want that to become 7 & 6, but in my case they are predefined, and are more than two single digits.

My first method:

static void nameSwitch (int[] array, int pos1, int pos2 ) {

    int temp = array[pos1];       /*As you all may know, this is the switching of 
    array[pos1] = array[pos2];    position 1 and 2.*/
    array[pos2] = temp;

}

My Second Method:

static void lastToFirstName() {
    int [] values = {1,2,3,4,5,6,7,8,9,10};
    for(//this is where I am stuck at.)


    System.out.println(Arrays.toString[values]);
 }

I want to output to be [21436587109], and the issue with me is getting to implement the method in the other method and getting the loop correct.

Answer 1

So it appears to me that you are switching every other term in values .

Original input:

int[] values = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

This can be accomplished in a for loop structured similar to this which 'jumps' to every other term and performs the switching operation accordingly:

for (int i = 0; i < values.length; i += 2) {
    nameSwitch(values, i, i + 1);
}

Final output:

values = {2, 1, 4, 3, 6, 5, 8, 7, 10, 9};

Edit: Adding compare functionality to the nameSwitch() method

You could edit nameSwitch() to take into consideration which number is greater; if pos1 is greater than pos2 , the switch would be conducted. Otherwise, pos1 is less than pos2 and the method would be immediately returned.

static void nameSwitch(int[] array, int pos1, int pos2) {

    if (pos1 < pos2) {
        return;
    }

    int temp = array[pos1];
    array[pos1] = array[pos2];
    array[pos2] = temp;

}

Answer 2

If I understand your question this code will work

static void nameSwitch (int[] array, int pos1, int pos2 ) {
    int temp = array[pos1];       /*As you all may know, this is the switching of position 1 and 2.*/
    array[pos1] = array[pos2];    
    array[pos2] = temp;

}
public static void main(String[] args) {
    int [] values = {1,2,3,4,5,6,7,8,9,10};
    int i;
    for(i = 0; i < values.length; i+=2) {
        nameSwitch(values, i, i+1);
    }
    System.out.println(Arrays.toString(values));
 }

Answer 3

Try this,

 for(int i=0;i+1<values.length;i=i+2)
 {
    nameSwitch(values, i, i+1);
  }

Yo need to increment i by 2 in each iteration so the next pair of numbers can be swapped with each other. i+1<values.length will ensure that if you have only one element remained for last iteration then it is kept as it is.

Answer 4

public class Switchnumbers {
public static void main(String[] args) {
    lastToFirstName();
}

static void lastToFirstName() {
    int[] values = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
    for (int i = 0; i < values.length; i = i + 2) {
        int tmp = values[i];
        values[i] = values[i + 1];
        values[i + 1] = tmp;
    }
    for (int i = 0; i < values.length; i++) {
        System.out.println(values[i]);
    }

}

}