im trying to split a string using a REGEX. The problem is that when splitting it adds an empty space to my String Array
public static String[] line;
line=this.classMetodos.split(meth.regexMethHead);
meth.regexMethHead being the regular expresion i want to split with.
the output given is the next one:
Metodos Contenido [0]:
Metodos Contenido [1]: {lol;}
Metodos Contenido [2]: {lol;}}
the output wanted is:
Metodos Contenido [0]: {lol;}
Metodos Contenido [1]: {lol;}}
Regex used
Regex used:
public static String regexAccess = "(public|private|\\s*)";
public static String regexStatic = "(static|\\s*)";
public static String regexReturnType = "(String|double|void)";
public static String regexMethName = "([a-z]|[A-Z])([a-z]|[A-Z]|[0-9])*";
public static String regexVariableName = "([a-z]|[A-Z])([a-z]|[A-Z]|[0-9])*";
public static String regexString = "\"([a-z]|[A-Z]|[0-9])*\"";
public static String regexArgs="(\\(\\)|\\(("+regexReturnType+"\\s*"+regexVariableName+")\\))";
public static String regexMethContent="\\{(.*|\\n*|\\t*)*\\}";
//complete regular expression
public static String regexMethHead = regexAccess +
"\\s*"+
regexStatic+
"\\s*"+
regexReturnType+
"\\s*"+
regexMethName+
"\\s*"+
regexArgs;
Input String
public static String meth= "public static void jenny(String lolito){\n\t lol;\n\n\t}";
public static String meth2= " public void Lolamer(String jeny){\n\t lol;\n\n\t}";
public static String variables ="static String e =\"lol\";";
public static String pseudoClass="public class torito{"+"\n"+variables+"\n"+
meth+"\n"+meth2+"}";
public static String regexClassName = "([a-z]|[A-Z])([a-z]|[A-Z]|[0-9])*";
public static String regexClassContent="\\{(.*|\\n*|\\t*)*\\}";
public static String regexCLass="^(public|private|\\s*)\\s*class\\s+"+
regexClassName+""+
regexClassContent+"";
Keep in mind my regex and String come from other class and im pulling them to make the split in another class
THANKS
我意识到,当您要拆分时,如果要拆分的表达式以REGEX中的某个值开头,则它假定那里有东西(在正则表达式用于拆分之前),因此这就是为什么要保存为空的原因一开始的空间。
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