How to get multiple outputs of random letters?

Question

I have a program and I need it to ask the user for a word eg hello and then ask for a pattern eg 2 and then take that word and split up the characters and put random letters between the letters of the word so in this case the users pattern was 3 so hello would be outputted as **h**as**e**rg**l**ty**l**oh**o** . So I have the part where I ask the user for a word and I spilt up the characters of the word with System.out.print(userWord.charAt(0));

I just need to know how you would generate random different letters each time between the words characters . The section of my code that generates the letters is this:

public static void main (String[] args)
{

    int cipherchoice = Integer.parseInt(JOptionPane.showInputDialog(null, "Please enter a number!"));

    int z;
    String  mixedarray1 [] = { "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z",};
    int x = mixedarray1.length;  // determines the length of mixedarray
    String[] myarray = new String [cipherchoice]; // create a new arracy to be coded

    for (int i = 0; i < cipherchoice; i++)  // loop equal size of coded array
    {  
      z = (int)(Math.random()*x); //  to create a random index value from mixedarray
      myarray[i] = mixedarray1[z]; // assigned myarray a random index value from mixedarray
      System.out.print (myarray [i]); // prints results using print (not println)
    }
}

So my output is System.out.print(myarray [i]); So how do you get multiple different outputs (Eg if the user enters 5 in another section of code how would you get 5 different outputs of random letters?

Answer 1

Put your code into a method and call it n times. Eg

void printRandomLetter() {
    ... the code you posted ...
}

...
void someOtherMethod() {
    for (int i = 0; i < userInput; i++) {
        printRandomLetter();
    }
}

Answer 2

Use the random.org service via HTTP , by issuing an HTTP GET request to https://www.random.org/strings/?num=10&len=8&digits=on&upperalpha=on&loweralpha=on&unique=on&format=html&rnd=new , in Java as follows:

URL url = new URL("https://www.random.org/strings/?num=10&len=8&digits=on&upperalpha=on&loweralpha=on&unique=on&format=html&rnd=new");
HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
conn.setRequestMethod("GET");
rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
while ((line = rd.readLine()) != null) {
     result += line;
}
rd.close();

Your strings will be in result. Exception handling is left as an exercise to the reader.