Lonely Integer - Output is correct. But still getting additional message

Question

Im trying to find the lonely integer in an array. My output is correct, but still getting the extra message. Please have a look at the code. I'm using Java to write the program.

Code:

import java.util.InputMismatchException;
import java.util.Scanner;

public class LonelyInteger {

    private static int inputArray[];
    private static int inputLength;
    private static final Scanner scanner = new Scanner(System.in);;

    public static void main(String[] args) {

        try {
            if (getInput()) {
                sortAndPrintArray();
                findLonelyInteger();
            } else {
                System.out.println("OOPS, something is not right! Try again!");
            }
        } catch (NumberFormatException | InputMismatchException nfime) {
            System.out.print("Number Format Exception or Input Mismatch Exception Occured: " + nfime);
        } catch (Exception e) {
            System.out.print("Exception Occured: " + e.getMessage());
        }

    }

    private static boolean getInput() throws NumberFormatException, InputMismatchException, Exception {

        System.out.print("Enter the array length: ");
        inputLength = scanner.nextInt();
        if (inputLength <= 0) {
            return false;
        }
        inputArray = new int[inputLength];
        System.out.println("Enter the array:");
        for (int i = 0; i < inputLength; i++) {
            inputArray[i] = scanner.nextInt();
        }
        return true;
    }

    private static void sortAndPrintArray() {
        sortArray();
        printSortedArray();
    }

    private static void sortArray() {
        int temp = 0;
        for (int i = 0; i < inputLength; i++) {
            for (int j = 0; j < i; j++) {
                if (inputArray[i] < inputArray[j]) {
                    temp = inputArray[i];
                    inputArray[i] = inputArray[j];
                    inputArray[j] = temp;
                }
            }
        }
    }

    private static void printSortedArray() {
        System.out.println("Sorted Array:");
        for (int i = 0; i < inputLength; i++) {
            System.out.print(inputArray[i] + " ");
        }
        System.out.println();
    }

    private static void findLonelyInteger() {
        boolean foundLonelyInteger = false;
        for (int i = 0; i < inputLength; i++) {
            if ((i+1) == inputLength) {
                System.out.println("Lonely Integer: " + inputArray[i]);
                break;
            }
            if (inputArray[i] == inputArray[++i]) {
                continue;
            } else {
                System.out.println("Lonely Integer: " + inputArray[i-1]);
                foundLonelyInteger = true;
                i--;
            }
        }
        if (!foundLonelyInteger) {
            System.out.println("Lonely integer not available!");
        }
    }

}

Here is my output, which is seen in Command Prompt:

Output:

Enter the array length: 5
Enter the array:
1
2
2
1
2
Sorted Array:
1 1 2 2 2 
Lonely Integer: 2
Lonely integer not available!

Answer 1

You did not set the flag, in your findLonelyInteger() method's first if condition!

if ((i+1) == inputLength) {
    System.out.println("Lonely Integer: " + inputArray[i]);
    foundLonelyInteger = true;  // --> HERE
    break;
}

Command Prompt? Start using Eclipse! And learn debugging!

Answer 2

Set your foundLonelyInteger = true; while you are checking for if((i+1) == inputLength)