I have my strings in my input
'ATTAGACCTG', 'CCTGCCGGAA', 'AGACCTGCCG', 'GCCGGAATAC'
In output I want the common shortest superstring.
ATTAGACCTGCCGGAATAC
I have completed it using the lambda expression but I want it without lambda expression.
from itertools import *
print min((reduce(lambda s,w:(w+s[max(i*(s[:i]==w[-i:])for i in range(99)):],s)[w in s],p)
for p in permutations(input())),key=len)
I tried it without using lambda expression and got wrong output.
from itertools import permutations
def solve(*strings):
"""
Given a list of strings, return the shortest string that contains them all.
"""
return min((simplify(p) for p in permutations(strings)), key=len)
def prefixes(s):
"""
Return a list of all the prefixes of the given string (including itself), in ascending order (from shortest to longest).
"""
return [s[:i+1] for i in range(len(s))]
return [(i,s[:i+1]) for i in range(len(s))][::-1]
def simplify(strings):
"""
Given a list of strings, concatenate them wile removing overlaps between
successive elements.
"""
ret = ''
for s in strings:
if s in ret:
break
for i, prefix in reversed(list(enumerate(prefixes(s)))):
if ret.endswith(prefix):
ret += s[i+1:]
break
else:
ret += s
return ret
print solve('ATTAGACCTG', 'CCTGCCGGAA', 'AGACCTGCCG', 'GCCGGAATAC')
My wrong output:
ATTAGACCTGCCGGAA
Looks as though
if s in ret:
break
should be
if s in ret:
continue
Think that will fix it.
Also the second return statement is surplus - doesn't it simulate reversed(list(enumerate(prefixes(s))))
anyway?
Finally, I think I prefer your initial map-reduce solution!
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