select statement in sql server to select every other row on alternate basis

Question

we have a table named "Result" have only one column say "Result". It contains 12 rows. First 6 rows contains "pass" and the next 6 rows contains "fail"

Result
---------------------
pass
pass
pass
pass
pass
pass
fail
fail
fail
fail
fail
fail

Now what would be the statement in SQL Query to return the return like below

Expected Result:-
pass
fail
pass
fail
pass
fail
pass
fail
pass
fail
pass
fail

Number of record may be in thousands but Query should work for all

Answer 1

in fact you need: the sequence of: one row from end, one row from beginning,...and so on until all rows get selected so make all passes as ODD and all fails as EVEN , now you can simply select and order by the number you made:

with CTE as
(
  select result , row_number() over(partition by result order by result) as rn
  from result
)
select result,
  case
  when result='fail' then rn*2 else rn*2 -1  end rn
from CTE 
order by rn

SQLFIDDLE DEMO

Answer 2

select result from (select row_number() over( order by result ) row_num,result from result where result='fail' union select row_number() over( order by result ) row_num,result from result where result='pass')a order by row_num

Works in Mssql