Split a string on every third space

Question

How can I split a string on every third space? I'm wondering if python has built-in syntax for this or if it can be done using a list comprehension.

"a bb c dd ee f" -> ["a bb c", "dd ee f"]

Answer 1

re.split(r'(.*?\s.*?\s.*?)\s', "a bb c dd ee f")

为了从结果中删除空字符串：

[x for x in re.split(r'(.*?\s.*?\s.*?)\s', "a bb c dd ee f") if x]

Answer 2

As a more general way you can use a function :

>>> def spliter(s,spl,ind):
...    indx=[i for i,j in enumerate(s) if j==spl][ind-1]
...    return [s[:indx],s[indx+1:]]
... 
>>> s="a bb c dd ee f"
>>> spliter(s,' ',3)
['a bb c', 'dd ee f']