How to search JSON data in MySQL?

Question

I have inserted records in mysql DB, with json encoded data type, Now I have to make search within json encoded data, but i am not able to get proper data using following MySql query.

SELECT  `id` ,  `attribs_json` 
FROM  `products` 
WHERE  `attribs_json` REGEXP  '"1":{"value":[^"3"$]'

Query results are key equal to "1" and value is anything except "3"

My data is:

{"feature":{"1":{"value":"["2","3"]"},
            "2":{"value":["1"]},
            "5":{"value":""},
            "3":{"value":["1"]},
            "9":{"value":""},
            "4":{"value":"\u0633\u0627\u062a\u0646"},
            "6":{"value":""},
            "7":{"value":""},
            "8":{"value":""}
           },
"show_counter":"0",
"show_counter_discount":""
}}

Answer 1

If you have MySQL version >= 5.7 , then you can try this:

SELECT JSON_EXTRACT(name, "$.id") AS name
FROM table
WHERE JSON_EXTRACT(name, "$.id") > 3

Output:

+-------------------------------+
| name                          | 
+-------------------------------+
| {"id": "4", "name": "Betty"}  | 
+-------------------------------+

Please check MySQL reference manual for more details:
https://dev.mysql.com/doc/refman/5.7/en/json-search-functions.html

Answer 2

如果您使用的是 MySQL 最新版本，以下可能有助于满足您的要求。

select * from products where attribs_json->"$.feature.value[*]" in (1,3)

Answer 3

1. Storing JSON in database violates the first normal form.

   The best thing you can do is to normalize and store features in another table. Then you will be able to use a much better looking and performing query with joins. Your JSON even resembles the table.

2. Mysql 5.7 has builtin JSON functionality:
   http://mysqlserverteam.com/mysql-5-7-lab-release-json-functions-part-2-querying-json-data/

3. Correct pattern is:

    WHERE `attribs_json` REGEXP '"1":{"value":[^}]*"3"[^}]*}'

   [^}] will match any character except }

Answer 4

I use this query

SELECT id FROM table_name WHERE field_name REGEXP '"key_name":"([^"])key_word([^"])"';
or
SELECT id FROM table_name WHERE field_name RLIKE '"key_name":"[[:<:]]key_word[[:>:]]"';

The first query I use it to search partial value. The second query I use it to search exact word.

Answer 5

For Mysql8->

Query:

SELECT properties, properties->"$.price" FROM book where isbn='978-9730228236' and  JSON_EXTRACT(properties, "$.price") > 400;

Data:

mysql> select * from book\G;
*************************** 1. row ***************************
id: 1
isbn: 978-9730228236
properties: {"price": 44.99, "title": "High-Performance Java Persistence", "author": "Vlad Mihalcea", "publisher": "Amazon"}
1 row in set (0.00 sec)

Answer 6

If MySQL version < 5.7

SELECT fields
FROM table
WHERE field_json LIKE '%"key":"70"%';

// 70 = value

Answer 7

Please do it like.

SELECT * FROM `products` 
    WHERE JSON_UNQUOTE(JSON_EXTRACT(`attribs_json`, '$.value')) LIKE '%X%'

Answer 8

SELECT
    country.NAME AS 'country_name',
    city.NAME AS 'city_name',
    city.district,
    city.info,
    JSON_EXTRACT( city.info, "$.Population" ) AS 'formated_population' 
FROM
    city
    INNER JOIN country ON city.CountryCode = country.
    CODE INNER JOIN countrylanguage ON country.CODE = countrylanguage.CountryCode 
GROUP BY
    city.NAME,
    city.district,
    country.NAME;

ORDER BY
    country.NAME ASC;

Answer 9

I think...

Search partial value:

SELECT id FROM table_name WHERE field_name REGEXP '"key_name":"([^"])*key_word([^"])*"';

Search exact word:

SELECT id FROM table_name WHERE field_name RLIKE '"key_name":"[[:<:]]key_word[[:>:]]"';

Answer 10

对于 MySQL 全部（和 5.7）

SELECT LOWER(TRIM(BOTH 0x22 FROM TRIM(BOTH 0x20 FROM SUBSTRING(SUBSTRING(json_filed,LOCATE('\"ArrayItem\"',json_filed)+LENGTH('\"ArrayItem\"'),LOCATE(0x2C,SUBSTRING(json_filed,LOCATE('\"ArrayItem\"',json_filed)+LENGTH('\"ArrayItem\"')+1,LENGTH(json_filed)))),LOCATE(0x22,SUBSTRING(json_filed,LOCATE('\"ArrayItem\"',json_filed)+LENGTH('\"ArrayItem\"'),LOCATE(0x2C,SUBSTRING(json_filed,LOCATE('\"ArrayItem\"',json_filed)+LENGTH('\"ArrayItem\"')+1,LENGTH(json_filed))))),LENGTH(json_filed))))) AS result FROM `table`;