How to make shell script launch python script?

Question

I need a .command file that can launch a python script in the same directory as it.

I have so far gotten this:

#!bin/bash
python /Users/username/Desktop/IF.py

But every time the Terminal returns the same error.

Last login: Sun Oct 11 01:48:38 on ttys000
MacBook-Pro:~ username$ /var/folders/m7/yf7p3vdj2mx0l9r7qb68rttc0000gn/T/Cleanup\ At\ Startup/run 466235498.368.command.command ; exit;
/var/folders/m7/yf7p3vdj2mx0l9r7qb68rttc0000gn/T/Cleanup At Startup/run-466235498.368.command.command: line 3: bin/bash: No such file or directory
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[Process completed]

Please note the error is on line 3 of the 2 lines of code I have...

Answer 1

Why not just launch the python script itself from the get-go? You can add a shebang at the top like so:

#! /user/bin/env python
... the rest of your python script here

Then just give the script executable permissions:

chmod +x nameofscript.py

Then just launch it like so:

./nameofscript.py

In case you don't want the script to rely on the environment, just use the following shebang instead:

#! /usr/bin/python

Answer 2

Maybe because the shebang (or hashbang ). About what is shebang (wiki) .

---

#!bin/bash
  ^ 
python /Users/username/Desktop/IF.py

This means the system will use bin/bash to run this program, but bin/bash means path/bin/bash .

For example, if you're in /home then the system will use /home/bin/bash to run this program.

---

I think you need this:

#!/bin/bash
python /Users/username/Desktop/IF.py

Note that I replaced #!bin/bash to #!/bin/bash .