On Ajax call from Angular controller, i am passing a complex object as data. On MVC controller object has all null values. I have MVC view as given below, which will be the boiler plate for Register customer View.
<div data-ng-app="customer" id="customer" data-ng-controller="rootViewModel">
<h2>{{ pageHeading }}</h2>
<hr />
<form id="formElement">
<div ng-view></div>
</form>
Using AngularJS, I will be loading the register customer view, mark of register customer view given below. I have register customer function tied to button using ng-click
directive.
<fieldset class="form-horizontal">
<div class="form-group">
<label class="control-label col-sm-3">Company Name</label>
<div class="col-sm-4">
<input class="form-control inputfieldValidation" ng-model="customer.Name" type="text" placeholder="Full company name" required autofocus />
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-3">PAN</label>
<div class="col-sm-4">
<input class="form-control" ng-model="customer.Pan" type="text">
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-3">TIN</label>
<div class="col-sm-4">
<input class="form-control inputfieldValidation" ng-model="customer.Tin" type="text" required />
</div>
</div>
<button class="btn btn-primary proceedNext" id="registerCompany" ng-click="registerCompany(customer)">Register Customer</button>
</fieldset>
I have angular controller, which has function called registerCustomer()
that will be called on click of register customer. I have an ajax call inside that function as given below.
customerModule.controller("CustomerRegistration", function ($scope) {
var initialize = function () {
}
$scope.registerCompany = function (customer) {
$.ajax({
url: 'Home/RegisterCompany',//make sure url exist
data: JSON.stringify({company: customer}),//pass data to action
type:'POST',
success: function (data) {
alert(JSON.stringify(data));
//window.location.href = '@Url.Action("Order")'; //redirect
}
});
}
initialize();
});
On MVC, i have a model called Company as given below.
public class Company
{
public string Name;
public string Pan;
public string Tin;
}
and my MVC controller look as
[HttpPost]
public JsonResult RegisterCompany(Company company)
{
//Do something
return null;
}
Always I have null object on MVC controller, please help me if am missing anything. Thanks in advance
EDIT: It looks like you need a view model in mvc or a modification to your post:
public class CompanyViewModel {
public Company company { get; set; }
}
Or use data: JSON.stringify(customer)
instead of data: JSON.stringify({ company: customer })
Here is a working example from a website we are developing. It uses Riot.js instead of angular, but the concepts will be similar.
See also http://www.abeautifulsite.net/postjson-for-jquery/
$.getJSON(self.baseUrl + "/SaveApplicant", $('form.#applicant').serialize(), function (response) {
if (response.errorMessage) {
RiotControl.trigger('error_message', response.errorMessage);
return;
} else {
self.packageQuote.applicant = response;
}
RiotControl.trigger("continue","applicant");
});
Or using post, per the link above
$.post(self.baseUrl + "/SaveApplicant", $('form.#applicant').serialize(), function (response) {
if (response.errorMessage) {
RiotControl.trigger('error_message', response.errorMessage);
return;
} else {
self.packageQuote.census = response;
}
RiotControl.trigger("continue","applicant");
},'json');
There is a bit more involved on the MVC side of things, to send back a json response with lower case property name prefixes:
public ActionResult SaveApplicant(Applicant model)
{
if (ModelState.IsValid)
{
var applicant = DbContext.Applicants.FirstOrDefault(row => row.Id == model.Id);
if (applicant == null) {
DbContext.Applicants.Add(model);
} else {
applicant.Clone(model); // implement as needed or use entity state modified.
}
DbContext.SaveChanges();
return FormattedJsonResult(applicant);
}
return ModelErrors();
}
public ActionResult FormattedJsonResult(object model)
{
var camelCaseFormatter = new JsonSerializerSettings();
camelCaseFormatter.ContractResolver = new CamelCasePropertyNamesContractResolver();
var result = JsonConvert.SerializeObject(model, camelCaseFormatter);
return Content(result, "application/json");
}
public ActionResult ModelErrors()
{
return FormattedJsonResult(
new
{
errorMessage =
String.Join("\n",
ModelState.Values.SelectMany(value => value.Errors).Select(error => error.ErrorMessage))
});
return View();
}
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