As per instructions: Write a static method that takes one integer as a formal parameter and returns a Boolean value of True if the parameter value is even and False if the it odd . It would seem my method must call an int instead of a boolean. With that being said I don't know how to return a boolean from a method that calls an int. I've tried this but it doesn't work.
EDIT - Language is JAVA. \\nEDIT 2 - For anyone looking at this in the future, I originally meant to type private static int result. Not private static boolean result. That mistake ended up fixing my code.
}
private static boolean result(int userIn)
{
if (userIn % 2 == 0)
{
int yes = 1;
return true;
}
else
{
return false;
}
}
Your original question didn't actually specify programming language, and it's not clear why you think you need to "call an int".
However in most C-descendent languages, and keeping with the style of your code quote, the following should work
private static boolean result(int userIn)
{
return (userIn % 2) == 0;
}
The expression (userIn % 2) == 0
will evaluate to a boolean (or your language's representation of one).
It is a common anti-idiom for people learning to program to do something like:
if (some condition is true)
then
return TRUE
else
return FALSE
Most (modern) programming languages allow you to simply return the result of evaluating a boolean condition, or to assign it to a suitably typed variable.
Thus
boolean result = (myvariable >= 10)
has the same result as, but is much more readable than:
boolean result
if (myvariable >= 10)
result = TRUE
else
result = FALSE
This may be what the person who set the assignment is wanting you to learn from it.
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