return value from python script to shell script

Question

I am new in Python. I am creating a Python script that returns a string "hello world." And I am creating a shell script. I am adding a call from the shell to a Python script.

1. i need to pass arguments from the shell to Python.
2. i need to print the value returned from Python in the shell script.

This is my code:

shellscript1.sh

#!/bin/bash
# script for testing
clear
echo "............script started............"
sleep 1
python python/pythonScript1.py
exit

pythonScript1.py

#!/usr/bin/python
import sys

print "Starting python script!"
try:
    sys.exit('helloWorld1') 
except:
     sys.exit('helloWorld2') 

Answer 1

You can't return message as exit code, only numbers. In bash it can accessible via $? . Also you can use sys.argv to access code parameters:

import sys
if sys.argv[1]=='hi':
    print 'Salaam'
sys.exit(0)

in shell:

#!/bin/bash
# script for tesing
clear
echo "............script started............"
sleep 1
result=`python python/pythonScript1.py "hi"`
if [ "$result" == "Salaam" ]; then
    echo "script return correct response"
fi

Answer 2

Pass command line arguments to shell script to Python like this:

python script.py $1 $2 $3

Print the return code like this:

echo $?