Print elements in list of tuple of tuple

Question

I have a list of tuples of tuples:

countries = [(('germany', 'berlin'),3),(('england', 'london'),90),(('holland', 'amsterdam'), 43)]

I am trying to return all items that match a specific string. So far I have this:

for i in countries:
   if i[0] == 'germany':
      print i

This returns:

('germany', 'berlin')

My desired output would be:

('germany', 'berlin'),3)

I have looked at list comprehension in the documentation but I cannot work out how to show the number for each tuple.

Answer 1

The code you are looking for is

for i in countries:
   if i[0][0] == 'germany':
      print i

Since you are a bit confused about the indexing:

i --> (('germany', 'berlin'),3)
i[0] --> ('germany,'berlin')
i[0][0] --> 'germany'

Answer 2

If you're building that data structure yourself, I'd recommend you to use a more explicit structure, like a dict or a namedtuple.

With your data structure, what you need is:

countries = [(('germany', 'berlin'),3),(('england', 'london'),90),(('holland', 'amsterdam'), 43)]
for country in countries:
    if country[0][0]:
        print(country)

While with a dict, you could have:

countries = [{'id': 3,
              'info': {'name': 'germany',
                       'capital': 'berlin'}},
             {'id': 90,
              'info': {'name': 'england',
                       'capital': london}}]
for country in countries:
    if country['info']['name'] == 'germany':
        print(country)

Which I personally think it's much easier to read. namedtuple is probably a better structure in this case, but it's slightly more complicated.

Answer 3

The current answer is sufficient, but if you want to check both items in the tuple for the string you could do this:

for i in countries:
    if 'germany' in i[0]:
        print i