I want to create an exception, preferebly with Try/catch from this code when I type a non-numeric character. I tried with int.TryParse, but this only return 0 when I use a non-numeric character. But don't show me any error message, but with int.Parse (Console.ReadLine) I got an error message:
The string of input characters was not in a correct format.
Code
while (true)
{
Console.WriteLine("TYPE A NUMBER HIGHER THAN 20: ");
int number;
number = int.Parse(Console.ReadLine());
if (number> 20)
{
Console.WriteLine("O NÚMERO DIGITADO FOI: " + number);
break;
}
else
{
Console.WriteLine(number+ " é menor do que 20, favor digitar um número maior");
}
}
Console.ReadLine();
You can create an exception like this:
Console.WriteLine("Type a number: ");
string line = Console.ReadLine();
try {
num = Int32.Parse(line);
}
catch (FormatException) {
Console.WriteLine("{0} is not an integer", line);
}
Or you can use int.TryParse
as you had mentioned:
Console.WriteLine("Type a number: ");
string line = Console.ReadLine();
if (!int.TryParse(line, out num)) {
Console.WriteLine("{0} is not an integer", line);
}
Instead of throwing an exception you should try to handle the input with Int32.TryParse (instead of Parse):
bool run = true;
while (run)
{
Console.Write("Type in a number: ");
string input = Console.ReadLine();
//Exit application
if(input == "exit")
{
run = false;
return;
}
//Returns true if numberStr can be parsed to an int
int number;
if (Int32.TryParse(input, out number))
{
//input is a number, now let's do some logic!
if(number > 20)
Console.WriteLine("Number is greater than 20!");
else
Console.WriteLine("Number is less than 20!");
}
else
Console.WriteLine("Doesn't seem to be a number: " + number);
}
Console.ReadLine();
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