regular expression to capture the string from the following pattern

Question

There is a string having the following pattern

Part1 : Part2

Part1 is a string without any “space” inside it, or this string can include anything except “space”. Part2 is another string which can have “space” inside. Between Part1 and Part2, the separator is “space””:””space”, ie, : How to write a regular expression to capture Part1. Thanks.

Answer 1

Try this

(.*?)(?>\s:)

Test Here

Answer 2

(\w+)\s:\s.*

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Answer 3

Please try this pattern:

^([^ ]+) : .*$

REGEX DEMO.