While loop did not ask for input

Question

Hi I just got into coding while on my sem break and now practicing by written a simple odd or even bet so I made a small UI as bellow

int Option()
{
    int UI;
    bool Conformation = 0;
    while (Conformation == 0)
    {
    cout << "For odd enter 1 , for even enter 2\n Insert : ";
    cin >> UI;
    Conformation = 0;
        switch (UI)
        {
        case 1:
            cout << "You have selected odd \n are you sure?\n 1.Yes 2.NO \n Insert :";
            cin >> Conformation;
            break;
        case 2:
            cout << "You have selected even \n are you sure? 1.Yes 2.NO \n Insert :";
            cin >> Conformation;
            break;
        default:
            cout << "Invalid entery please enter another value\n";
            Conformation = 0;
            break;
        }
    }
    return UI;
}

I expected it to loop through line 8 "cin >> UI;" when Conformation = 0 , but it just skip any form of "cin"

thank in advance.

Answer 1

You have:

cout << "You have selected odd \n are you sure?\n 1.Yes 2.NO \n Insert :";
cin >> Conformation;

Use of 1 or 2 for Confirmation is most likely tripping you up since Confirmation is of type bool .

I suggest changing the type of Confirmation to int .