var coordinates =(Coordinates[])values["Coordinates"];
Console.WriteLine(coordinates[0].Easting);
Console.WriteLine(coordinates[0].Northing);
To get just two values:
var easting = values["Coordinates"][0].Easting;
var northing = values["Coordinates"][0].Northing;
Explanation: since values
is a dictionary :
values["Coordinates"] - get value (i.e. array) of "Coordinates" key
values["Coordinates"][0] - get 1st item of the array of "Coordinates" key
values["Coordinates"][0].Easting - get Easting property of ...
Let values
be the Dictonary and the "Coordinates"
is a Key inside it. So that we can access the associated values with this key by using values["Coordinates"]
. In your case the value will be a collection(Array). So To access those values you need to Specify its index or you can iterate through the collection to get it's values. As you already said it was a Dictonary<string,Object>
You need to cast the object to get the Business object. If so you can use The following snippet:
var currentEasting = (Coordinates[])(values["Coordinates"][0]).Easting;
If the collection is defined like Dictonary<string,Coordinates>
then you need not to cast. Can access it directly like this:
var currentEasting = values["Coordinates"][0].Easting;
You can also iterate through those Values; this code will help you to do that:
foreach (Coordinates Co in values["Coordinates"])
{
// access each values
var someEasting = Co.Easting
}
It is a bit unclear how the dictionary is defined. If it is defined as Dictionary<string, object>
, you will either have to use reflection to get data from the value, or you will have to do a hard-coded cast:
var coords = (Coordinates[])values["Coordinates"];
var firstEast = coords[0].Easting;
This will of course fail if the object is not of type Coordinates.
If the dictionary is defined as Dictionary<string, Coordinates[]>
, then it is simple:
var firstEast = values["Coordinates"][0].Easting;
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.