I want to store the find command output in a variable and use it many times as find command consumes time.
abc=`find . -maxdepth 3 -type f -name "abc.txt"`
echo "${abc[*]}" | xargs grep -l "somestring1"
echo "${abc[*]}" | xargs grep -l "somestring2"
echo "${abc[*]}" | xargs grep -l "somestring3"
But it only greps on the first element of array abc.
Since you're using nonstandard -maxdepth
, I'm assuming non-standard find
that handles the -print0
predicate, so as to safely build an array :
abc=()
while IFS= read -r -d '' f; do
abc+=( "$f" )
done < <(find . -maxdepth 3 -type f -name "abc.txt" -print0)
There you have an array abc
.
Now, you can safely pass the array abc
as arguments to grep
:
grep -l "somestring1" "${abc[@]}"
grep -l "somestring2" "${abc[@]}"
grep -l "somestring3" "${abc[@]}"
Note 1. In your code, abc
is not an array.
Note 2. I have no idea why you say your code doesn't work… it should work (provided you have nice filenames without spaces and quotes); maybe you're not showing the full code?
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