Matching a phone number at the end of a string with `regex`, and return both parts

Question

I have a bunch of lines like the following:

Name1 Surname1         +44 (020) 1234 5678 
Name2 Name2 Surname2   +39 (051) 12.34.56
Surname3, Name3      -     (555) 123-456-789
Surname4, Name4 Name4       123 - 456.78.90

and I would like to identify and return the names and the numbers that they contain. For instance, I would like to return:

1. Name1 Surname1 +44 (020) 1234 5678
   • name: Name1 Surname1
   • number: +44 (020) 1234 5678
2. Name2 Name2 Surname2 +39 (051) 12.34.56
   • name: Name2 Name2 Surname2
   • number: +39 (051) 12.34.56
3. Surname3, Name3 - (555) 123-456-789
   • name: Surname3, Name3 -
   • number: (555) 123-456-789
4. Surname4, Name4 Name4 123 - 456.78.90
   • name: Surname4, Name4 Name4
   • number: 123 - 456.78.90

I'm using Java regex and, so far, I came up to the following pattern:

\A(.*)\s+(\+?\s*\d+([.-\s]*(\d+|\(\d+\)))+)\z

If line is any of above lines, the code to match the pattern is:

Pattern pattern = Pattern.compile("^(.*)\\s+(\\+?\\s*\\d+([.-\\s]*(\\d+|\\(\\d+\\)))+)$");
Matcher matcher = pattern.match(line);
if (matcher.find()) {
    System.out.println("Name: " + pattern.group(1));
    System.out.println("Number: " + pattern.group(2));
}

Unfortunately, on any line ( Name1 Surname1 +44 (020) 1234 5678 , for instance) it returns the following:

Name: Name1 Surname1         +44 (020) 1234
Number: 5678

I think that the reason for this result is the regex being too greedy, but I don't understand how to modify its behaviour.

Can anyone please correct the pattern and explain me the solution in simple terms? I read a few tutorial without understanding what to do. Thanks in advance!

Answer 1

The simplest I can think of right now would be

^(.*?)\s*((?:\+|\()[-\d(). ]*)

It captures everything up to the spaces preceding a + or a ( . Then it captures everything after that (being digits, hyphens, parentheses, dots or spaces) to a second group.

Check it out here at regex101 .