If you have Two class list how can you compare them to see if they are the same regardless of order.
Class[] list1[class1, class1, class2]
Class[] list2[class2, class1, class1]
These list are the same regardless of order but how can java Boolean this? eg
if(list1.sort == list2.sort){}
The best solution will be to add Guava
and use MultiSet
.
HashMultiset<Class> hms1 = new HashMultiSet<>();
HashMultiset<Class> hms1 = new HashMultiSet<>();
for (Class c : list1) {
hms1.add(c);
}
for (Class c : list2) {
hms2.add(c);
}
if (hms1.equals(hms2) {
//lists are the same in your understanding of the same
}
Simpler solution would be to use Map<Class, Integer>
HashMap<Class, Integer> hm1 = new HashMap<>();
HashMap<Class, Integer> hm2 = new HashMap<>();
for (Class c : list1) {
if (!hm1.containsKey(c)) {
hm1.put(c, 1);
} else {
hm1.put(c, hm1.get(c)+1);
}
}
for (Class c : list2) {
if (!hm2.containsKey(c)) {
hm2.put(c, 1);
} else {
hm2.put(c, hm2.get(c)+1);
}
}
if (hm1.equals(hm2) {
//lists are the same in your understanding of the same
}
Class<?>[] list1 = new Class[] { String.class, String.class, Integer.class };
Class<?>[] list2 = new Class[] { Integer.class, String.class, String.class };
Comparator<Class<?>> classComparator = new Comparator<Class<?>>() {
@Override
public int compare(Class<?> o1, Class<?> o2) {
return o1.getCanonicalName().compareTo(o2.getCanonicalName());
}
};
Arrays.sort(list1, classComparator);
Arrays.sort(list2, classComparator);
if (Arrays.equals(list1, list2)) {
System.out.println("same regardless of order");
} else {
System.out.println("NOT same regardless of order");
}
The above prints
same regardless of order
I am modifying the original lists. You may want to take copies first if this is not desired.
Arrays.equals()
is using Class.equals()
, which in turn is just Object.equals()
. As long as there is only one Class object for each Class, this works. I believe that this holds true as long as you are using only one class loader. So be warned that it's a bit subtle here.
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