How to match a string and ignore everything after it?

Question

So here is the deal, I want to match a number and a string that comes after it. Like a buying list, "10 bananas" or "15 apples". The problem is, the same regex has to match "10 banana" but can't match "10 banana milkshake".

Regexes I already tried:

r"\b[0-9]{1,5}.banana"
r"\b[0-9]{1,5}.banana\b"
r"\b[0-9]{1,5}.banana$"

Example:

8 banana 3 banana ice cream 2 banana milkshake 5 banana

From that string, I need to match only "8 banana" and "5 banana".

With the regexes I tried, it matches "X banana" as expected, but I want it to be exactly "X banana" (where X is a number that appears 1-5 times, as in the regex) and ignore if it has anything else after it, like "ice cream" or "milkshake" in this example. Also, the "$" sign doesn't match anything if I put it on the regex.

Answer 1

use re.findall with lookahead regex below, it assert banana must be following by digit or end of string. s? after banana to match plural bananas as well

import re
s = '8 banana 3 banana ice cream 2 banana milkshake 5 banana'
match = re.findall(r'\b[0-9]{1,5}.bananas?(?=\s?\d+|$)', s)
# ['8 banana', '5 banana']