Regex for number between special characters

Question

I want to build a regex that will extract me numbers from a string. The pattern is

">number<"

Now the number can have decimals or not. I went with:

"[^\d]+"

This does extract the numbers but because of decimals, it sometimes works bad. Any ideas?

Answer 1

试试这个（用引号复制）：

">[0-9]+(\.[0-9]+)?<"

Answer 2

A simple regex which works for integers, floats and negative numbers :

>([\+\-]?\d+\.?\d*)<

The number is in group 1.

If you can use positive lookarounds, this regex matches just a number between >< and nothing else :

(?<=>)[\+\-]?\d+\.?\d*(?=<)

Here in action.

Answer 3

>((\-|\+)?[0-9]+(\.[0-9]+)?)<

Explained:

• (\\-|\\+)? optional sign: - or +
• [0-9]+ - non-empty sequence of digits
• (\\.[0-9]+)? - optional sequence starting with a dot followed by non-empty sequence of digits
• > and < at the beginning and at the and (not in the matching group)

In the first matching group you will have your number.

Example here .

Answer 4

Assuming that it's just the number you want:

(?<=\\>)[0-9]+(\.[0-9]+)?(?=\<)

It matches any number with or without decimals between > and < but excluding > and <