Python/Regex - Replace by pattern only at the end of string

Question

I need to replace every parenthesis at the end of a string. I use this code:

a = '1 (FR) Product (IT, DE, ES)'
b = re.sub(r' \((.*?)\)',r'', a)

But this will replace every parenthesis in my string. How do I tell python to replace it only if the pattern is at the end of the string?

Answer 1

Capture everything but ( before ) and end of string identifier $ :

>>> import re
>>> a = '1 (FR) Product (IT, DE, ES)'
>>> re.sub(r'\(([^(]*\))$', '', a)
'1 (FR) Product '

Answer 2

if a[-1] == ")" a = a[:-2]将起作用