Regular Expression to find the exact match of the string

Question

Hi I have records like

MicroAlgae 7.5
AlgaeSerum 6.5
Algae 1.5

Here i need to extract the value of algae that is 1.5 and it should not extract the values of microalgae and algaeserum. I have used the regex as

/(?!Micro)/Algae,
Algae\s*/^(!Serum)/,
\\bAlgae\\b

Kindly let me know how can I write the regex according to that

Answer 1

If you have some large text where you need to pull the number from, you may use a simple regex with a capturing group around the part you need to extract:

import re
s = """MicroAlgae 7.5
AlgaeSerum 6.5
Algae 1.5"""
m = re.search(r'\bAlgae\s+([0-9.]+)', s)
if m:
    print(m.group(1))

See the Python demo

The [0-9.]+ may be replaced with a more precise [0-9]+(?:\\.[0-9]+)? .

Details :

• \\b - the leading word boundary
• Algae - the literal char sequence Algae
• \\s+ - one or more whitespaces
• ([0-9.]+) - Group 1: one or more digits or dots or
• [0-9]+(?:\\.[0-9]+)? - 1+ digits ( [0-9]+ ), followed with an optional sequence of a . ( \\. ) and 1+ digits ( [0-9]+ ).