why does “aabbcc”[/ab*/] only return “a”?

Question

如果量词*表示“零次或多次”，则似乎"aabbcc"[/ab*/]应返回"abb"但仅返回"a" 。

Answer 1

The regex returns exactly what you asked : the first occurence of 1 a followed by 0 or more b .

If you want all the non-overlapping occurences, you could use scan :

"aabbcc".scan(/ab*/)
#=> ["a", "abb"]

If you want to have a least 1 b , you could use b+ :

"aabbcc"[/ab+/]
#=> "abb"

Answer 2

好的，所以我才知道这是因为最左边的比赛获胜并且因为在abb之前有a匹配的a才返回。