Remove dictionary from list with multiple conditions

Question

list1 = [
   {'id': 1, 'country': 'Italy'},
   {'id': 2, 'country': 'Spain'},
   {'id': 3, 'country': 'Japan'}
]

I use this code to remove from list1 every dictionary that has country != Italy :

list2 = [element for element in list1 if element['country'] == 'Italy']

But I to include in list2 dictionaries which country == 'Italy' AND country == 'Spain' and remove all the others (or even better pop them from list1 without creating another one). How can I do this in one line=

Answer 1

如果您真的想要单线，则可以将列表理解与就地列表更新一起使用：

list1[:] = [d for d in list1 if d['country'] in ('Spain', 'Italy')]