Python Network Interface Scan

Question

I need to create a Python script that queries the network interfaces and returns me the name of the host, the IP address, and the mac address.

#!/usr/bin/env python3
import netifaces

x = netifaces.interfaces()
i = x[0]

for i in x:
    if i != 'lo':

        print(i)
        face = netifaces.ifaddresses(i)

        print(face)
        i += i
    else:
        continue

This is one version of the program I am working with. This seems to grab all the data that I need but I cannot get it to print clean or correctly! I am looking for something like: "Nic: wlan0, ipaddr: 10.0.0.1, mac: 4651168584541"

I am new to programming and very new to python so please any help is appreciated!

Answer 1

Please check the links:

1. @camflan's response in Getting MAC Address

2. How to get the physical interface IP address from an interface

    import netifaces x = netifaces.interfaces() for i in x: if i != 'lo': print(i) print("mac:" + netifaces.ifaddresses(i)[netifaces.AF_LINK][0]['addr'] + " ipaddr:" + netifaces.ifaddresses(i)[netifaces.AF_INET][0]['addr']) i += i else: continue 

Answer 2

So this was a little tricky at first but this format should allow you to grab data from the results of netifaces.

import netifaces

x = netifaces.interfaces()


for i in x:
    if i != 'lo':
    print('\nInterface: ' + i)
    mac = netifaces.ifaddresses(i)[netifaces.AF_LINK][0]['addr']
    print('Mac addr: ' + mac)

    try:
        ip = netifaces.ifaddresses(i)[netifaces.AF_INET][0]['addr']

        print('IP addr: {0} '.format(ip))
    except KeyError:
        print('NO IP')
        continue

Output will look as follows:

Interface: eth0
Mac add: eo:ie:9:38:ri
No IP

Interface: wlan0
Mac addr: 34:po:iu:66
IP addr: 10.0.0.1