jq get first value by priority and condition

Question

I have following json:

{
  "Detail": {
    "Response": [
      {
        "ID": "8000000D-1483989576",
        "Name": "",
        "FullName": "FullName 1"
      },
      {
        "ID": "8000000C-1483985849",
        "Name": "Name 1"
      },
      {
        "ID": "80000006-1481277410",
        "Name": "Name 2",
        "FullName": "FullName 2"
      },
      {
        "ID": "8000000B-1481537384",
        "Name": "Name 3"
      }
    ]
  }
}

I'm trying to create another json that will consider the non-empty/not null .Name as priority otherwise get .FullName regardless if it's empty or null, the final json would look like following:

[
  {
    "id": "8000000D-1483989576",
    "name": "FullName 1"
  },
  {
    "id": "8000000C-1483985849",
    "name": "Name 1"
  },
  {
    "id": "80000006-1481277410",
    "name": "FullName 2"
  },
  {
    "id": "8000000B-1481537384",
    "name": "Name 3"
  }
]

The temporary solution I got is to use join

jq '[.Detail.Response[] | {id: .ID, name: [.Name, .FullName] | join("") }]'

But of course, it'll only work if .FullName is empty or null.

Answer 1

This should get you on your way:

.Detail.Response[]
| { id: .ID, Name: (if .Name != "" then .Name else .FullName end) }

Answer 2

我找到了一种方法来使用map和select来做到这一点。

jq '[.Detail.Response[] | {id: .ID, name: [.Name, .FullName] | map(select(length > 0)) | first }]'