I need to generate A 32bit random and unique number in hex representation

Question

Following code is what I have done so far

    Random randomeNum =  new Random();
    int n = randomeNum.nextInt();
    System.out.println(Integer.toHexString(n));

Is this a correct way doing it?

Answer 1

您可以使用UUID生成32位随机十六进制数。

 UUID id=randomUUID();